Answer to Question #15454 in Mechanics | Relativity for Daniela
The velocity of a watermelon has zero value at the peak of its flight.
(b) its acceleration
The acceleration of a watermelon has zero value at the peak of its flight too.
(c) the elapsed time
We can write down the next
V = V0 - gT,
where V is the current velocity of a watermelon, V0 = 12 m/s is the initial velocity of a watermelon, g is the gravity acceleration and T is the time elapsed after firing. As the velocity of a watermelon has zero value at the peak of its flight, we can find the time elapsed by watermelon to reach the peak:
V0 - gT = 0 ==> T = V0/g = 12[m/s]/9.8[m/s²] ≈ 1.22 s.
(d) its height above the ground?
H = H0 + gT²/2 = 1.20[m] + 9.8[m/s²]*(1.22[s])²/2 ≈ 8.49 m.
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