# Answer to Question #15433 in Mechanics | Relativity for dharshan

Question #15433

a cracker of mass 100 g explodes into 2 equal mass . show that these 2 pieces of cracker flies inopposite direction

Expert's answer

In a closed system (one that does not exchange any matter with the outside

and is not acted on by outside forces) the total momentum P =const.

P = M

* V0, where M = 100 g, V0 = 0. So, P = 0.

After the explosion, P = m1 * V1 +

m2 * V2, where m1 = m2 = M / 2.

(M / 2) * V1 + (M / 2) * V2 = 0

V1 + V2 =

0

V1 = - V2, so these 2 pieces of cracker should fly in opposite directions.

and is not acted on by outside forces) the total momentum P =const.

P = M

* V0, where M = 100 g, V0 = 0. So, P = 0.

After the explosion, P = m1 * V1 +

m2 * V2, where m1 = m2 = M / 2.

(M / 2) * V1 + (M / 2) * V2 = 0

V1 + V2 =

0

V1 = - V2, so these 2 pieces of cracker should fly in opposite directions.

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