Answer to Question #15405 in Mechanics | Relativity for Tatiana
T = V/|a| = 100[m/s]/(|-0.5[m/s²]|) = 200 s,
therefore the stop distance is
D = |a|T²/2 = 0.5[m/s²]*(200[s])²/2 = 10000 m > 800 m.
So, a plane can't land at an airport.
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