Answer to Question #15182 in Mechanics | Relativity for judy
H = gT²/2,
where H is the height of the table, g is the gravity acceleration and t is falling time. So, it will take
T = √(2H/g) = √(2*1[m]/9.81[m/s²]) ≈ 0.45 seconds
for the ball to hit the floor. The velocity of the ball just before it hits the floor will be
V = gT = 9.81[m/s²]*0.45[s] ≈ 4.41 m/s.
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