Question #1507

The tire on a bicycle is filled with air to a
gauge pressure of 658 kPa at 20 degrees C.
What is the gauge pressure in the tire after
a ride on a hot day when the tire air temperature is 60 degrees C? (Assume constant volume and a
constant atmospheric pressure of 101.3 kPa.)
Answer in units of kPa.

Expert's answer

For the constant volume we use Gay-Lussac's law:

P_{1}/T_{1}= P_{2}/T_{2}

Thus P_{2} = P_{1}T_{2}/T_{1}

For our case P_{1} = 658 + 101.3 = 759.3 kPa (absolute pressure); T_{1} = 20C = 293 K; T_{2} = 60C = 333 K.

P_{2} = 759.3*333/293 = 862.9 kPa.

The gauge pressure is P = P_{2} -P_{atm} = 862.9-101.3 = 761.66 kPa

P

Thus P

For our case P

P

The gauge pressure is P = P

## Comments

Assignment Expert22.08.13, 16:56You're welcome. We are glad to be helpful.

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Jake19.08.13, 23:42Thanks so much for the help!!

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