Answer to Question #15054 in Mechanics | Relativity for nautavia
A car slows down from 25 m/s to rest in a distance of 93 m. What was its acceleration, assumed constant?
Let's find out the deceleration time of a car:
V = at ==> t = V/a
We know that
L = at²/2,
a = 2L/t² = 2L/(V/a)² = 2La²/V²,
1 = 2La/V² ==> a = V²/(2L).
a = 25²/(2*93) ≈ 3.3602 m/s².
So, the acceleration of a car was approximately -3.3602 m/s².