Answer to Question #15054 in Mechanics | Relativity for nautavia
V = at ==> t = V/a
We know that
L = at²/2,
a = 2L/t² = 2L/(V/a)² = 2La²/V²,
1 = 2La/V² ==> a = V²/(2L).
a = 25²/(2*93) ≈ 3.3602 m/s².
So, the acceleration of a car was approximately -3.3602 m/s².
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