Question #15049

A 6.0-kg object is pulled along a frictionless horizontal surface by a horizontal force of 24 N. If the object is at rest at t = 0 , how fast is it moving after 3.0 seconds (in m/s)?

Expert's answer

Let's find the acceleration of an object using the second Newton's law:

F = ma ==> a = F/m

Now we can find the object's velocity:

V = at = Ft/m = 24[N]*3.0[s]/6.0[kg] = 12.0 [m/s].

So, it will move with the speed of 12.0 m/s after 3.0 seconds.

F = ma ==> a = F/m

Now we can find the object's velocity:

V = at = Ft/m = 24[N]*3.0[s]/6.0[kg] = 12.0 [m/s].

So, it will move with the speed of 12.0 m/s after 3.0 seconds.

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