Answer to Question #15049 in Mechanics | Relativity for Cora
A 6.0-kg object is pulled along a frictionless horizontal surface by a horizontal force of 24 N. If the object is at rest at t = 0 , how fast is it moving after 3.0 seconds (in m/s)?
Let's find the acceleration of an object using the second Newton's law:
F = ma ==> a = F/m
Now we can find the object's velocity:
V = at = Ft/m = 24[N]*3.0[s]/6.0[kg] = 12.0 [m/s].
So, it will move with the speed of 12.0 m/s after 3.0 seconds.