A cessna aircraft has a lift-off speed of 120km/h. (a) what minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 240 m? (b) how long does it take the aircraft to become airborne?
(a) As V0 = 0, then the equation of the speed is the following: V = at, and the equation of the covered distance: S = at^2 / 2 where a - acceleration.
V = 120 km/h = 100 / 3 m/s. After multiplying the first equation by t and division by the second equation we get:
V^2 / S = 2a, a = V^2 / (2S) = 10000 / (9 * 2 * 240) = 2.31 m / s^2.