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Answer to Question #14913 in Mechanics | Relativity for mohamed alarayyed

Question #14913
A baseball is thrown horizontally from a height of 122.5 m above the ground with a speed of 26.5 m/s. Where is the ball after 5.00 s has elapsed?




horizontal



m from the launch position



vertical



m from the ground
Expert's answer
horizontal m from the launch position
L=((26.5)^2)*122.5/10=8602.56

vertical m from the ground
L=((26.5)^2)/20=25.11

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