Answer to Question #148622 in Mechanics | Relativity for Nitsuj

Question

A force of magnitude 200N is directed west, and a second force of magnitude 100N is directed east of north. Find the magnitude and direction of a third force that, when added to the first two forces, gives a resultant whkse magnitude is zero

Answer 1

Using formula R = (R₁² + R₂² - 2*R₁*R₂*cos$\theta$ )^0.5, net magnitude of can be obtained.

$\theta$ = (90+45)$\degree$ in this case.

F_r is resultant force initially applied.

F_o is opposing force needed to make net force 0.

The Resultant Direction of first two forces, F_r, would be west of north.

So, The direction of third force, F_o, would be East of South.

Magnitude of F_o would be 147.36 N