Answer to Question #147853 in Mechanics | Relativity for blablabla

Question #147853
An alarm clock is dropped off the edge of a tall building. You, standing directly under it, hear a tone of 1350 Hz coming from the clock at the instant it hits the ground (you jumped out of the way at the last moment- whew!) Since you know the building is 25.0 m tall, you can find out what the frequency of the alarm would be if you had just held it in your hands. What would that frequency be?
1
Expert's answer
2020-12-02T07:32:21-0500

Answer

Doppler effect formula when moving sound source is given by

"f=\\frac{f_0 v_s}{v_s\\pm v_0}" ........ eq. 1

In case of observer is moving

"f=f_0\\frac{v_s\\pm v_0}{v_s}"

"f_0" Is frequency of source.=1350nm

h= height of building

So putting all value in eq. 1 then frequency is found is

"f=1263Hz"


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