The weight of water provided the force on the wheel to turn the axle. If the axle provides 3750N of force, and the effective weight of the water can provide a tangent force on the wheel of 325N, what is the minimum radius of the wheel if the axle radius is 55 cm.
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Expert's answer
2011-02-03T08:09:35-0500
Let's write the condition of equilibruim of the torques: F1d1 = F2d2 3750*0.55 = 325*d2 d2 = 3750*0.55/325 ≈ 6.35 m. Answer: the minimum radius of the wheel is equal approximately to 6.35 m.
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