# Answer to Question #14327 in Mechanics | Relativity for Annette

Question #14327

A car accelerates from rest at a constant rate of 2 m/s2 for 5 s. a) What is the speed of the car at the end of that time? b) How far does the car travel in this time?

Expert's answer

a)

The equation for the speed is:

V(t) = V0 + a * t = a * t, as V0 =

0.

Then V(5) = 2 * 5 = 10 m/s.

b)

The equation for the covered

distance is:

S = V0 * t + a * t^2 / 2 = a * t^2 / 2, as V0 = 0.

Then S = 2

* 5^2 / 2 = 25 m.

The equation for the speed is:

V(t) = V0 + a * t = a * t, as V0 =

0.

Then V(5) = 2 * 5 = 10 m/s.

b)

The equation for the covered

distance is:

S = V0 * t + a * t^2 / 2 = a * t^2 / 2, as V0 = 0.

Then S = 2

* 5^2 / 2 = 25 m.

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment