a body is attached to alower end of aspring suspended from the foot of a lift .when the lift is at rest,a body produces an elongation of 2cm in the spring. when the lift moves downward with an acceleration ,the elongation is changed to 1.95 cm. find the acceleration of the lift.
When the lift is at rest, a body produces an elongation of dl1 = 2 cm in the spring. When the lift moves downward with an acceleration, the elongation is changed to dl2 = 1.95 cm. dl = F * k dl1 = m * g * k dl2 = m * (g + a) * k dl1 / dl2 = g / (g + a) a = g * dl2 / dl1 - g a = 9.81 * 1.95 / 2.00 - 9.81 = -0.24525 So, the acceleration of the lift is a = -0.24525 m/s^2.
The moment you’ve entered the education system is the moment you start to realize that, although studying is extremely important,…
APPROVED BY CLIENTS
This website is actual legit!! I was realllly skeptical at first, and I thought this was a scam but it actually isn’t. They have a whollle youtube channel Where they teach about different subjects. I had an economics assignment that I left till last minute and it was very hard. I just needed 5% to pass that class so I gave this website a chance. The price I was given was USD and once I converted it to CAD it was a lot! But it was worth it because I got a 34/37 on my assignment & I passed the class! They got the assignment done 1 hour before the due date, and were very professional! if I ever need help on one of my assignments Again I am 100% coming back here again. 10/10 would recommend!