Answer to Question #14137 in Mechanics | Relativity for jinan haneefc
When the lift moves downward with an acceleration, the elongation
changed to dl2 = 1.95 cm.
dl = F * k
dl1 = m * g * k
dl2 = m * (g
+ a) * k
dl1 / dl2 = g / (g + a)
a = g * dl2 / dl1 - g
a = 9.81 * 1.95
/ 2.00 - 9.81 = -0.24525
So, the acceleration of the lift is a = -0.24525
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