Answer to Question #1396 in Mechanics | Relativity for Mike
3.1 cm. The tube is sealed at one end and
loaded with lead shot to give it a total mass
of M = 88 g. The tube floats in water (of
density 1 g/cm3) in vertical position, loaded
What is the depth of the bottom end of the
Answer in units of cm.
Denote the depth of the bottom end as H, the volume of the tube under the surface would be V = H πd2/4.
ρ g V = M g
V = M / ρ = 88 [g] / 1 [g/cm3] = 88 cm3.
H πd2/4 = 88.
H = 4*88 / 3.14* 3.12 = 11.7 cm.
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