Answer to Question #13681 in Mechanics | Relativity for shaz
V = at = 1 [m/s²] * 20 [s] = 20 [m/s].
Time needed to stop the cycle that moves at 20 m/s with deceleration of 2 m/s² is
T = 20 [m/s] / 2 [m/s²] = 10 [s].
So, the total distance travelled is
L = 1*20²/2 + 30*60 + 2*10²/2 = 2100 m.
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