# Answer to Question #13681 in Mechanics | Relativity for shaz

Question #13681

A cyclist moves his cycle from rest with an acceleration of 1m/s squared, for 20 seconds and then he moves with uniform velocity for 1 minute. Finally he applies brakes and stops with a negative acceleration of 2 m/s squared. Determine total distance covered by the cyclist.

Expert's answer

The velocity cyclist obtains after 20 seconds is

V = at = 1 [m/s²] * 20 [s] = 20 [m/s].

Time needed to stop the cycle that moves at 20 m/s with deceleration of 2 m/s² is

T = 20 [m/s] / 2 [m/s²] = 10 [s].

So, the total distance travelled is

L = 1*20²/2 + 30*60 + 2*10²/2 = 2100 m.

V = at = 1 [m/s²] * 20 [s] = 20 [m/s].

Time needed to stop the cycle that moves at 20 m/s with deceleration of 2 m/s² is

T = 20 [m/s] / 2 [m/s²] = 10 [s].

So, the total distance travelled is

L = 1*20²/2 + 30*60 + 2*10²/2 = 2100 m.

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