Question #13602

Derive an expression for the work done when a body is pulled down along the inclined plane with constant speed.

Expert's answer

Let α be the incline angle. Then gravitation force projection onto the plane is

F1 = mg/cosα.

The friction force F2 is directed opposite to the F1. The body is moving with constant speed, so the total force is equal to zero:

F1 + F2 = 0.

If so, the work done is equal to zero too.

F1 = mg/cosα.

The friction force F2 is directed opposite to the F1. The body is moving with constant speed, so the total force is equal to zero:

F1 + F2 = 0.

If so, the work done is equal to zero too.

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