Answer to Question #13432 in Mechanics | Relativity for harisha
A block of mass 2*1000g moving at 2*100m/s collides with another block of same mass at rest. if actual loss of K.E. is half of the maximum then the coefficient of restitution is
KE1max = m * V^2 / 2 = 2 * 200^2 / 2 = 40000 J Loss is KE1 = KE2 = KE1max / 2 = 20000 J. So, after the impact V1 = V2. The coefficient of restitution is given by C = (Vb - Va) / (Ua - Ub) for two colliding objects, where Va is the final velocity of the first object after impact Vb is the final velocity of the second object after impact Ua is the initial velocity of the first object before impact Ub is the initial velocity of the second object before impact C = (V2 - V1) / (200 - 0) = 0
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