# Answer to Question #13257 in Mechanics | Relativity for hanusha

Question #13257

two bodies of masses 2kg &8kg have kinetic energies 16J&24J respectively. when they are moving in the same direction . they collide each other. the total momentum after collision is

Expert's answer

KE = m * V^2 / 2, so V = sqrt(2 * KE / m).

The total momentum P of the two

bodies is the same before the

collision as it is after the collision.

P =

m1 * V1 + m2 * V2

P = m1 * sqrt(2 * KE1 / m1) + m2 * sqrt(2 * KE2 / m2)

P

= sqrt(2 * KE1 * m1) + sqrt(2 * KE2 * m2)

P = sqrt(2 * 16 * 2) + sqrt(2 * 24

* 8) = 27.6 kg*m/s.

The total momentum P of the two

bodies is the same before the

collision as it is after the collision.

P =

m1 * V1 + m2 * V2

P = m1 * sqrt(2 * KE1 / m1) + m2 * sqrt(2 * KE2 / m2)

P

= sqrt(2 * KE1 * m1) + sqrt(2 * KE2 * m2)

P = sqrt(2 * 16 * 2) + sqrt(2 * 24

* 8) = 27.6 kg*m/s.

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