Question #130091

The viscosity of a fluid is to be measured by a

viscometer constructed of two 40-cm-long

concentric cylinders (adjacent Fig.). The outer

diameter of the inner cylinder is 12 cm, and

the gap between the two cylinders is 0.15 cm.

The inner cylinder is rotated at 300 rpm, and

the torque is measured to be 1.8 N m.

Determine the viscosity of the fluid?

viscometer constructed of two 40-cm-long

concentric cylinders (adjacent Fig.). The outer

diameter of the inner cylinder is 12 cm, and

the gap between the two cylinders is 0.15 cm.

The inner cylinder is rotated at 300 rpm, and

the torque is measured to be 1.8 N m.

Determine the viscosity of the fluid?

Expert's answer

What is given:

Gap between two concentric cylinders = "1 mm"

The frequency of inner cylinder = "300 rpm"

Length of the concentric cylinders, "L=75 cm"

Torque acting "1.8 N m."

Outer diameter of the inner cylinder="15 cm"

"\\mu=\\frac{Te}{4\\pi^2R^3\\dot{n}L}\n=\\frac{(1.8N.m)(0.0015m)}{4\\pi^2(0.06m)^3(300\/601\/s)(0.4m)}"

="0.158N.s\/m^2"

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