Question #130016

A metre rule is balanced on a knife edge at it's centre of gravity G . A mass of 40g is placed at a distance of 30cm from G and another mass x g placed at 10cm from G on the other side kept the ruler in equilibrium. What is the value of x

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Expert's answer

To keep lever in equilibrium, the moments of torque must be balanced. Moments are "M = F \\cdot l", where F is applied force, l - distance between the force and the fulcrum. "F = mg".

"M_1=M_2 \\Rightarrow m_1gl_1 = x g l_2"

"m_1l_1 = xl_2"

"x = \\frac{m_1l_1}{l_2}= \\frac{40*30}{10} = 120" g.

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