Question #128833

0.05 m3 of a gas at 6.9 bar expands reversibly in a cylinder behind a piston according to the law pv1.2= Constant, until the volume is 0.08 m3. Calculate the work done by the gas and sketch the process on a p-v diagram.

Expert's answer

For PV"^{\\gamma}" = constant

work done by the gas = "\\frac{(P_2V_2-P_1V_1)}{(1-\\gamma)}" where "\\gamma = 1.2"

for calculation of "P_2 = P_1(\\frac{V_1}{V_2})^{1.2}"

"P_2= 6.9(\\frac{0.05}{0.08})^{1.2}"

P_{2}= 3.92bar

hence work done="\\frac{3.92\\times0.08-6.9\\times0.05}{1-1.2}"

work done by gas = 0.0157 bar m^{3}

and the PV is given below:

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