Question #128588

A load of mass M1 = 2.3kg is attached to a mass M2=4.25 with a light inextensible string hanging over a frictionless pulley.If the two loads hang freely in air what is the acceleration of m1 upwards

Expert's answer

We may conclude the smaller load to move upwards, so its acceleration "a" is directed upwards. Let us now determine the forces that act on the loads.

M1: "M_1 a = T-M_1g" , where T is the tension of string,

M2: "M_2a = M_2g-T," therefore,

"(M_1+M_2)a = (M_2-M_1)g, \\;\\; \\\\\n a = \\dfrac{M_2-M_1}{M_1+M_2}\\cdot g = \\dfrac{4.25\\,\\mathrm{kg}-2.3\\,\\mathrm{kg}}{4.25\\,\\mathrm{kg}+2.3\\,\\mathrm{kg}}\\cdot 9.8\\,\\mathrm{N\/kg} = 2.9\\,\\mathrm{m\/s}^2."

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Amelia06.08.20, 00:02Thank you so much

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