Question #127761

what is the resultant of displacement of 6 miles north and 9 miles east?

Expert's answer

We may note that the displacements are perpendicular to each other, so we may use Pythagorean theorem to obtain the total displacement.

The total displacement is "S=\\sqrt{l_1^2+l_2^2} =\\sqrt{6^2+9^2}\\approx 10.8" miles. Next, we should determine the angle "\\theta" of the displacement with respect to the north.

"\\cos\\theta=\\dfrac{6}{10.8} , \\, \\theta \\approx 56^\\circ."

So now we know the total distance and the direction of the displacement.

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