Answer to Question #12656 in Mechanics | Relativity for mohamed
kinetic energy after 10 sec time?
F = ma ==> a = F/m = 30N /6kg = 5 m/s².
The velocity of an object after 10 seconds will be
V = at = 5m/s² * 10s = 50m/s.
So, the kinetic energy of an object after 10 seconds will be
E = mV²/2 = 6kg * (50m/s)² /2 = 7500J.
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