Question #12656

An object of 6 kg mass was at rest. After that a 30 N force is imposed on it. What will be

kinetic energy after 10 sec time?

kinetic energy after 10 sec time?

Expert's answer

Let's find the acceleration of an object using the second Newton's law:

F = ma ==> a = F/m = 30N /6kg = 5 m/s².

The velocity of an object after 10 seconds will be

V = at = 5m/s² * 10s = 50m/s.

So, the kinetic energy of an object after 10 seconds will be

E = mV²/2 = 6kg * (50m/s)² /2 = 7500J.

F = ma ==> a = F/m = 30N /6kg = 5 m/s².

The velocity of an object after 10 seconds will be

V = at = 5m/s² * 10s = 50m/s.

So, the kinetic energy of an object after 10 seconds will be

E = mV²/2 = 6kg * (50m/s)² /2 = 7500J.

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