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# Answer to Question #126474 in Mechanics | Relativity for Stefanie Hernandez-Mendez

Question #126474
Suppose a 200-mm focal length telephoto lens is being used to photograph mountains 12.5 km away.
What is image distance, in meters, for this lens?
What is the image height, in centimeters, of a 950-m high cliff on one of the mountains?
1
2020-07-20T15:02:58-0400

The lens formula is used to obtain the image distance

"\\frac{1}{f}=\\frac{1}{u}+\\frac{1}{v}"

"\\frac{1}{v}=\\frac{1}{f}-\\frac{1}{u}"

"\\frac{1}{v}=\\frac{ 1}{0.2}-\\frac{1}{12500}"

"v= 0.2 meters"

image distance= 0.2m

To get the image height , magnification should first be calculated

"m=\\frac{imagedistance}{object distance}"

"m=\\frac{ 0.2}{12500}= 1.6\\times10^{-5}"

"m=\\frac{ height of image}{heightof object}"

"heightofimage= (1.6\\times10^{-5})\\times950=0.0152 m"

height of image in cm is 1.52 cm

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