Question #125751
A contraption shows the following m1 = 2.0 x 103 kg, m2 = 4.4 x 102 kg, the man on top of m2 has a mass m = 6.0 x 101 kg, and all surfaces are frictionless. What is the apparent weight of the man?
1
Expert's answer
2020-07-10T10:26:35-0400

The weight of the man


P=mg=6.0⋅101⋅9.81=588.6NP=mg=6.0\cdot10^1\cdot9.81=588.6N


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