Question #124504

A particle of mass 10 kg is attached to one end of a light inextensible string whose other end is fixed. The particle is pulled aside by a horizontal force until the string is at 60° to the vertical. Find the magnitude of the horizontal force and the tension in the string.

Expert's answer

The sum of forces' vectors is "\\overrightarrow{0}" : "\\overrightarrow{R} = m\\overrightarrow{a} = \\overrightarrow{F} + \\overrightarrow{T} + m\\overrightarrow{g} = \\overrightarrow{0}"

Horizontal direction: "F = T \\cdot sin60^\\circ;"

Vertical direction: "T \\cdot cos 60^\\circ = mg;"

Then "T = \\dfrac{mg}{cos60^\\circ} = \\dfrac{mg}{1\/2} = 2mg;" "F = T \\cdot sin60^\\circ = 2mg \\cdot \\dfrac{\\sqrt{3}}{2} = \\sqrt{3}mg"

m is known from the task and g you should take with the necessary accuracy.

Learn more about our help with Assignments: MechanicsRelativity

## Comments

## Leave a comment