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# Answer to Question #123782 in Mechanics | Relativity for Ojugbele Daniel

Question #123782
The angular velocity of a disc of mass 3kg and radius 0.6m change from 10rev/s to 15rev/s in 0.07s. calculate the impulse on the disc.
1
2020-06-29T14:14:04-0400

Angular momentum L (which change disc speed) can be found:

"L=J*(\\omega_{2} - \\omega_{1})"

where J - disc's moment of inertia, ω2 - finish angular speed ω1 - start angular speed.

Moment of inertia for disc can be found:

"J= \\frac{m\\times r^2}{2}"

where m - mass of the disc, r - radius of the disc.

Angular speed for correct calculation have to be transformed from rev/s to rad/s.

So we have:

"L=\\frac{m\\times r^2\\times(\\omega_{2}-\\omega_{1})}{2}"

"L=\\frac{3\\times0.62\\times(15\\times2\\times\\pi - 10\\times2\\times\\pi)}{2}=16.956 \\frac{kg\\times m^2}{s}"

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