Answer to Question #12287 in Mechanics | Relativity for jim murillo
m1·u1 + m2·u2 = m1·v1 + m2·v2.& (1)
Here m1 is the mass of the first object (11.7 kg), m2 is the mass of the second object (3.9 kg), u1 and u2 are initial velocities of the first and the second objects respectfully and v1 and v2 are their velocities after collision.
The equation expressing conservation of kinetic energy is
m1·u1² + m2·u2² = m1·v1² + m2·v2².& (2)
Using expressions (1) and (2) we'll get
v1 = (m1-m2)·u1/(m1+m2) + 2·m2·u2/(m1+m2),
or, substituting given masses and initial velocities
v1 = (11.7-3.9)·0/(11.7+3.9) + 2·3.9·18/(11.7+3.9) = 9 m/s.
So, 11.7 kg object obtain speed 9 m/s.
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