Question #122550

Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle. At the bottom of the dive, the speed of the airplane is 390 m/s. What is the smallest radius allowable for the vertical circle if the pilot's apparent weight is not to exceed 5.0 times his true weight?

Expert's answer

"5mg-mg=\\frac{mv^2}{r}\\\\4g=\\frac{v^2}{r}\\\\4(9.8)=\\frac{390^2}{r}"

"r= 3900\\ m"

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