76 836
Assignments Done
Successfully Done
In June 2019

Answer to Question #1224 in Mechanics | Relativity for faith

Question #1224
A box is dropped from a spacecraft moving horizontally at 27.0 m/s at a distance of 155 m above the surface of a moon. The rate of freefall acceleration on this airless moon is 2.79 m/s2. (a) How long does it take for the box to reach the moon's surface? (b) What is its horizontal displacement during this time? (c) What is its vertical velocity when it strikes the surface? (d) At what speed does the box strike the moon?
Expert's answer
For the vertical velocity projection the equations of the motion are:
v = at
h = at2/2;

v= 2.79 t
155 = 2.79t2/2.
a) t = 10.54 s.
b) Sh = 27 m/s * 10.54s = 284.58 m
c) Vv = 2.79 * 10.54 = 29.4 m/s
d) V = sqrt (Vh2 + Vv2) = sqrt (272 + 29.42) = 39.9 m/s

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions