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# Answer to Question #118719 in Mechanics | Relativity for nikil

Question #118719
In the system shown, a horizontal force Fx = 40 N acts on an object of mass m2 = 8.00 kg. A friction force fk = 5 N acts between object m2 and the table top, and m1 = 2.00 kg. i) Calculate the acceleration of the masses. ii) Calculate the tension in the string.
1
2020-05-28T13:23:39-0400

"2\\; Newton's\\; law:\\\\1)\\;F_{fr2}=\\mu\\times m_2\\times g;\\mu=\\frac{F_{fr}}{m_2\\times g}=\\frac{5}{8\\times 9.8}=0.064\\\\\\\\(m_1+m_2)\\times a=F_x-F_{fr1}-F_{fr2}\\\\a=\\frac{40-0.064\\times 2\\times 9.8-5}{10}=3.375\\frac{m}{s^2};\\\\2)\\;m_1\\times a=T-F_{fr1};T=m_1\\times a+F_{fr1}\\\\T=2\\times3.375+0.064\\times 2\\times 9.8=\\\\=6.75+1.25=8N;\\\\Answer:\\;the\\; acceleration\\; of\\; the\\; masses:\\\\3.375\\frac{m}{s^2};the \\;tension\\; in\\; the\\; string:8N"

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