Question #117500

1. A force of 48.0 N is required to start a 6.0 Kg box moving across a horizontal

concrete floor.

a) What is the coefficient of static friction between box and floor?

b) If the 48.0 N force continues, the box accelerates at 0.70m/s2

, what is the

coefficient of kinetic friction?

concrete floor.

a) What is the coefficient of static friction between box and floor?

b) If the 48.0 N force continues, the box accelerates at 0.70m/s2

, what is the

coefficient of kinetic friction?

Expert's answer

Given data :

Force "F = 48N"

Mass of box "m = 6 Kg"

Normal Reaction "N=mg= 6 \\times 9.81 N = 58.86 N"

Frictional Force "F_{Frictiona} = F = 48 N"

Static Friction "\\mu_{Static} = \\frac {F_{Friction}} {N}"

**Static Friction:**

** **"\\mu_{Static} = \\frac {48} {58.86} = 0.815"** **

**Kinetic Friction :**

"\\mu_{Kinetic} = \\frac {F-F_{Acceleration}} {N}"

"\\mu_{Kinetic} = \\frac {48 - 6\\times 0.70 } {58.86} = 0.744"

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