Question #116744

I drag a mass m=21 kg in a straight line, along a horizontal surface, a distance D= 23m .I drag it at constant speed v=0.90m/s in a straight line using a horizontal force.the coefficient of static friction is 1.2 and coefficient of kinetic friction is 1.1.How much work do I do in joules?

Expert's answer

As the object is in motion hence kinetic friction will take place

kinetic friction = "\\mu_k\\times N=1.1\\times21\\times10" ="231 N"

lets apply work energy theorem

"\\sum W=\\Delta K"

"W_N+W_f+W_{mg}+W_F=\\Delta K"

"0-(231\\times23)+0+W_F=\\frac12\\times21\\times0.9^2"

"W_F=5321.5 J"

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