# Answer to Question #1164 in Mechanics | Relativity for anon

Question #1164

A 7.6 kg chair is pushed across a frictionless floor with a force of 42 N that is applied at an angle of 22° downward from the horizontal. What is the magnitude of the acceleration of the chair?

Expert's answer

The horizontal projection of the force applied to the chair is

F

According ot the sewcond Newton's law,

a = F

F

_{h}= Fcos (α) = 42 cos(22°) = 38.9 N.According ot the sewcond Newton's law,

a = F

_{h}/m = 38.9 / 7.6 = 5.11 m/s^{2}Need a fast expert's response?

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