Answer to Question #1164 in Mechanics | Relativity for anon
A 7.6 kg chair is pushed across a frictionless floor with a force of 42 N that is applied at an angle of 22° downward from the horizontal. What is the magnitude of the acceleration of the chair?
The horizontal projection of the force applied to the chair is
Fh = Fcos (α) = 42 cos(22°) = 38.9 N.
According ot the sewcond Newton's law,
a = Fh/m = 38.9 / 7.6 = 5.11 m/s2