Question #116367

A biker is heading in the positive y direction with initial velocity 9.0 m/s. Her acceleration is given by a=[4.1,-2] m/s2.

How far is the biker from the point she started at the instance she reaches the maximum in y coordinate?

How far is the biker from the point she started at the instance she reaches the maximum in y coordinate?

Expert's answer

The maximum in y coordinate will be when

"x=0.5a_xt^2=0.5(4.1)(4.5)^2=41.5125\\ m"

"y=vt-0.5a_yt^2=(9)(4.5)-0.5(2)(4.5)^2\\\\=20.25\\ m"

"s=\\sqrt{41.5125^2+20.25^2}=46\\ m"

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