Question #11507

A torque of 12 Nm is applied to a disk of radius 0.50m. If the disk accelerates at 5.7 rad/s^2 what is the mass of the disk?

Expert's answer

Torque = moment of inertia x angular acceleration

Moment of inertia = 0.5 * m

* r * 2

T = 0.5 * m * r * 2 * a

12 = 0.5 * m * 0.50 * 2 * 5.7

m = 12 /

(0.5 * 0.50 * 2 * 5.7) = 4.21 kg

Moment of inertia = 0.5 * m

* r * 2

T = 0.5 * m * r * 2 * a

12 = 0.5 * m * 0.50 * 2 * 5.7

m = 12 /

(0.5 * 0.50 * 2 * 5.7) = 4.21 kg

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