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Answer to Question #11501 in Mechanics | Relativity for gian

Question #11501
An egg is thrown upward from a point near a cornice of a tall building.It just misses the cornice on the way down and passes a point 120 ft below its starting point 5.00 sec after it leaves the thrower's hand. a. what is the initial speed of the egg? b. how high does it rise above its starting point?. c.what is the magnitude of its velocity at the highest point? d. what are the magnitude and direction of its acceleration at the highest point?
Expert's answer
120 ft = approx. 36.576 m
h + 36.576 = g * t^2 / 2, h = g * t^2 / 2 -
36.576
h = 9.81 * 5^2 /2 - 36.576 = 86.049
Let tu is the time to move an
egg to the highest point.
V0 = g * tu, tu = V0 / g
h = V0 * tu - g * tu^2
/2
h = V0^2 / g - g * (V0 / g)^2 /2
h = V0^2 / g - V0^2 / (2 * g) = V0^2
/ (2 * g)
V0 = sqrt(2 * g * h)
V0 = sqrt(2 * 9.81 * 86.049) =
sqrt(1688.28138) = 41.089 m/s

a. what is the initial speed of the
egg?
V0 = 41.089 m/s = approx. 135 ft/s
b. how high does it rise above its
starting point?.
h = 86.049 m = approx. 282 ft
c.what is the magnitude of
its velocity at the highest point?
V = 0
d. what are the magnitude and
direction of its acceleration at the
highest point?
a = g = 9.81 m/s^2,
the acceleration is directed downwards

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