Question #11501

An egg is thrown upward from a point near a cornice of a tall building.It just misses the cornice on the way down and passes a point 120 ft below its starting point 5.00 sec after it leaves the thrower's hand. a. what is the initial speed of the egg? b. how high does it rise above its starting point?. c.what is the magnitude of its velocity at the highest point? d. what are the magnitude and direction of its acceleration at the highest point?

Expert's answer

120 ft = approx. 36.576 m

h + 36.576 = g * t^2 / 2, h = g * t^2 / 2 -

36.576

h = 9.81 * 5^2 /2 - 36.576 = 86.049

Let tu is the time to move an

egg to the highest point.

V0 = g * tu, tu = V0 / g

h = V0 * tu - g * tu^2

/2

h = V0^2 / g - g * (V0 / g)^2 /2

h = V0^2 / g - V0^2 / (2 * g) = V0^2

/ (2 * g)

V0 = sqrt(2 * g * h)

V0 = sqrt(2 * 9.81 * 86.049) =

sqrt(1688.28138) = 41.089 m/s

a. what is the initial speed of the

egg?

V0 = 41.089 m/s = approx. 135 ft/s

b. how high does it rise above its

starting point?.

h = 86.049 m = approx. 282 ft

c.what is the magnitude of

its velocity at the highest point?

V = 0

d. what are the magnitude and

direction of its acceleration at the

highest point?

a = g = 9.81 m/s^2,

the acceleration is directed downwards

h + 36.576 = g * t^2 / 2, h = g * t^2 / 2 -

36.576

h = 9.81 * 5^2 /2 - 36.576 = 86.049

Let tu is the time to move an

egg to the highest point.

V0 = g * tu, tu = V0 / g

h = V0 * tu - g * tu^2

/2

h = V0^2 / g - g * (V0 / g)^2 /2

h = V0^2 / g - V0^2 / (2 * g) = V0^2

/ (2 * g)

V0 = sqrt(2 * g * h)

V0 = sqrt(2 * 9.81 * 86.049) =

sqrt(1688.28138) = 41.089 m/s

a. what is the initial speed of the

egg?

V0 = 41.089 m/s = approx. 135 ft/s

b. how high does it rise above its

starting point?.

h = 86.049 m = approx. 282 ft

c.what is the magnitude of

its velocity at the highest point?

V = 0

d. what are the magnitude and

direction of its acceleration at the

highest point?

a = g = 9.81 m/s^2,

the acceleration is directed downwards

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