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# Answer to Question #114455 in Mechanics | Relativity for Jason Grace

Question #114455

Thank-you!

You and a colleague are on a spacewalk, repairing your spacecraft that has stalled in deep space. Your 90.0 kn colleague, initially at rest, asks you to throw her a hammer, which has a mass of 3.0 kg. You throw it to her with a velocity of 4.5 m/s [forward].

a) What is her velocity after catching the hammer?

b) What impulse does the hammer exert on her?

c) What percentage of kinetic energy is lost in the collision?
1
2020-05-12T09:32:28-0400

(a)initial momentum = final momentum

So

"3\\times4.5= (3+90)\\ v\\\\or\\\\v=0.1452\\ m\/s"

(b) impulse = change in momentum of hammer=

"m(v-4.5)=3(0.1452-4.5)=13. 0644\\ kg-m\/s"

(C) initial kinetic energy =

"\\frac{1}{2}m\\times4.5^2=0.5\\times 3\\times 20.25=30.375\\ J"

Final kinetic energy

"\\frac{1}{2}(90+3)(0.1452)=6.7518\\ J"

Percentage loss in energy = "\\frac{30.375-6.7518}{30.375}\\times100= 77\n.77\\ percent"

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