Answer to Question #112842 in Mechanics | Relativity for Obanor junoir

Question

The ice point and steam point on a thermometer are found to be 96.0mm apart. What temperature is recorded when the length of mercury thread is 33.6mm above the ice point mark

Answer 1

As per the question,

The ice point on the thermometer =96.0mm

recorded length of the mercury =33.6mm

Let the required temperature is x,

$\dfrac{x-0}{100-0}=\dfrac{33.6-0}{96-0}$

$\Rightarrow x=\dfrac{33.6\times 100}{96}^\circ C$

$x=35^\circ C$