Answer to Question #11265 in Mechanics | Relativity for William
t^2+100=4vt where v is in m/s and t is in seconds.Find the possible values of v.
explain the complete solution of my question step by step.
Now, to the possible values.
We cant calculate v when t=0 (divizion by 0). Also, t can not be negative, so v too. Then we find the minimum for v(t).
v'(t)=-25/t^2+1/4=0 so t=10 is a local minimum.
Minimal value for v is v(10)=(100+100)/40=5m/s maximum is any.
So the answer - v is equal or greater than 5 m/s.
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