The acceleration given this system
Fx=mgsin(15.2°)=ma→a=gsin(15.2°)=2.57m/s2F_x=mg\sin(15.2°)=ma\to a=g\sin(15.2°)=2.57m/s^2Fx=mgsin(15.2°)=ma→a=gsin(15.2°)=2.57m/s2
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