Question #111741

The planet Earth orbits the sun with a period of one year. In this problem, you may assume the radius of the Earths orbit is 1.50x10^8 km.

(A) Calculate the Earths average speed relative to the sun in meters per second.

(B) what is the earths average velocity relative to the sun over a period of one year in meters per second?

(A) Calculate the Earths average speed relative to the sun in meters per second.

(B) what is the earths average velocity relative to the sun over a period of one year in meters per second?

Expert's answer

Solution (A): The earth's orbit around the sun insignificantly differs from a circular one. This means that its path is equal to the circumference of the circle "S=2\\pi R=2\\cdot 3.14\\cdot 1.50\\cdot 10^8km=9.42\\cdot 10^{11}m". This is the path the Earth travels in the year in which it is contained "t=1year=365 [day]\\cdot 24 [hour]\\cdot 60 [min]\\cdot 60s=3.15\\cdot 10^7 s"

By determining the average speed we write "v=\\frac{S}{t}=\\frac{9.42\\cdot 10^{11}m}{3.15\\cdot 10^7 s}=3.0\\cdot 10^4m\/s" .

Solution (B): Relative to the sun the earth each year returns to the same point from which it started moving a year ago. Therefore relative to the sun it passes zero distance "\\vec D=\\vec 0 m" per year. By determining the average velocity we write "\\vec V=\\frac {\\vec D}{t}=\\vec 0" m/s.

Answers: (A) the Earths average speed relative to the sun in meters per second is "3.0\\cdot 10^4m\/s"

(B) The earths average velocity relative to the sun over a period of one year is "0 m\/s"

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Amy10.09.21, 06:43This helped a ton! Thanks so much!! :)

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