# Answer to Question #111399 in Mechanics | Relativity for marie

Question #111399
The large quadriceps muscle in the upper leg terminate at the lower end in a tendon attached to the upper end of the tibia. The forces on the lower leg are defined as: T is the tension in the tendon, w is the force of gravity acting on the lower leg, and F is the weight of the foot.
Find T when the tendon is at an angle of 25o with the tibia, assuming w=120N,F=20Nandthelegisextendedatanangleof40o with respect to the vertical. Assume that the center of gravity of the lower leg is at its center and that the tendon attaches to the lower leg at a point one fourth of the way down the leg
1
2020-04-24T10:52:07-0400 "-\\frac{d}{2}w_y-dF_y+\\frac{d}{4}T_y=0"

"-\\frac{d}{2}w\\sin{\\theta}-dF\\sin{\\theta}+\\frac{d}{4}T\\sin{\\theta'}=0"

"-\\frac{1}{2}120\\sin{40}-20\\sin{40}+\\frac{1}{4}T\\sin{25}=0"

"T=487\\ N"

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