Question #110686

A 0.010-kg bullet is fired from a 5.0-kg gun with a muzzle velocity of 230 m/s. Call the direction in which the bullet is fired from the +x direction .

Part A:

While the bullet is traveling in the barrel,what is the ratio of the acceleration of the gun to the acceleration of the bullet ?

Part B:

What is the speed of the bullet relative to the ground at the instant the bullet leaves the barrel?

Part A:

While the bullet is traveling in the barrel,what is the ratio of the acceleration of the gun to the acceleration of the bullet ?

Part B:

What is the speed of the bullet relative to the ground at the instant the bullet leaves the barrel?

Expert's answer

"m_1v_1=m_2v_2\\\\0.01*230=5*v_2"

"v_2=0.46 m\/s"

As the momentum on both sides is same and lets assume that the momentum change is in "\\Delta t" time

then force is equal to "\\frac{\\Delta P}{\\Delta t }=ma"

"m_1a_1=m_2a_2"

"\\frac{m_1}{m_2}=\\frac{a_2}{a_1}"

"\\frac{a_2}{a_1}=\\frac{5}{0.01}=500"

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