Answer to Question #109746 in Mechanics | Relativity for dsd

Question

Question text
A 35.4 g bullet strikes a 18.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off together at 13.3 m/s.



What was the initial velocity of the bullet?

Answer 1

We write the law of conservation of momentum in the projection onto the axis X

$m \cdot u=(m+M) \cdot V$

where will we write

$u= \frac{(m+M)}{m} \cdot V=\frac{(0.0354+18)}{0.0354} \cdot 13.3=6776 m/s=6.776 km/s$