Question #109746

Question text

A 35.4 g bullet strikes a 18.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off together at 13.3 m/s.

What was the initial velocity of the bullet?

A 35.4 g bullet strikes a 18.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off together at 13.3 m/s.

What was the initial velocity of the bullet?

Expert's answer

We write the law of conservation of momentum in the projection onto the axis X

"m \\cdot u=(m+M) \\cdot V"

where will we write

"u= \\frac{(m+M)}{m} \\cdot V=\\frac{(0.0354+18)}{0.0354} \\cdot 13.3=6776 m\/s=6.776 km\/s"

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