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# Answer to Question #109635 in Mechanics | Relativity for Ankur kumar

Question #109635
rabbit run across a parking lot on which set of coordinates axes has been drawn. The coordinates (in metres) of the rabbits position as function of time (in second) are given by:-
x= -0.32t² + 7.2t + 28
y= 0.22t² - 9.1t + 30
At t=15 s, what is the rabbits position for r in unit vector notation and in magnitude angle notation?
i. Draw a graph for rabbits path for t= 0 to t= 25 s
ii. Find the rabbits velocity v at time t= 15 s
iii. Find the rabbits acceleration 'a' at time t= 15 s.
1
2020-04-15T10:21:12-0400

Given:

"x(t)=-0.32t^2+7.2t+28"

"y(t)=0.22t^2-9.1t+30"

The rabbit position at "t=15\\:\\rm s"

"{\\bf r}=64{\\hat i}-57{\\hat j}=(86; 318\\degree)"

(i) rabbit path

(ii) rabbit velocity

"{\\bf v}=-2.4{\\hat i}-2.57{\\hat j} \\:(\\rm m\/s)"

(iii) rabbit acceleration

"{\\bf a}=-0.64{\\hat i}+0.44{\\hat j} \\:(\\rm m\/s^2)"

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