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Answer to Question #109511 in Mechanics | Relativity for dsfd
Question #109511
A 8.21 kg bowling ball traveling at 14.66 m/s strikes a 2.1 kg bowling pin. The impact slows the bowling ball to 9.97 m/s.
Determine the change in momentum of the pin.
Determine the change in momentum of the pin.
Expert's answer
"m_0v_0=m_0v+mu"
"\\Delta p=mu=m_0v_0-m_0v=m_0(v_0-v)=8.21(14.66-9.97)=38.5\\frac{kg\\cdot m}{s}"
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