Answer to Question #109494 in Mechanics | Relativity for atta

Question #109494
particles p and Q leave a fixed point A at the same time and travel in the same straight line. the velocity of P after t seconds is 6t(t-3)ms-1 and the velocity of Q after t seconds is (10-2t)ms-1.
1) sketch,on the same axes, velocity-time graph for P and Q for 0<=t<=5
2)verify that P and Q meet after 5 seconds.
3)find the greatest distance between P and Q for 0<=t<=5
1
Expert's answer
2020-04-15T10:16:06-0400

1)



2) After 5 seconds:


S1=v(t)dt=(6t218t)dt=(2t39t2)05=25S_1=\int v(t)dt=\int(6t^2-18t)dt=(2t^3-9t^2)|_0^5=25


S2==v(t)dt=(102t)dt=(10tt2)05=25S_2==\int v(t)dt=\int(10-2t)dt=(10t-t^2)|_0^5=25

3)



f(t)=v2tv1tf(t)=v_2t-v_1t


f(t)=10t2t26t3+18t2f(t)=10t-2t^2-6t^3+18t^2


f/(t)=18t2+32t+10f^/(t)=-18t^2+32t+10

t1t \approx1

f(1)=20f(1)=20


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